n^2=0.0036

Solution for n^2=0.0036 equation:

n^2=0.0036

We move all terms to the left:

n^2-(0.0036)=0

We add all the numbers together, and all the variables

n^2-0.0036=0

a = 1; b = 0; c = -0.0036;
Δ = b2-4ac
Δ = 02-4·1·(-0.0036)
Δ = 0.0144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0144}}{2*1}=\frac{0-\sqrt{0.0144}}{2}
=-\frac{\sqrt{}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0144}}{2*1}=\frac{0+\sqrt{0.0144}}{2}
=\frac{\sqrt{}}{2}
$